Relevance. Find the equation of the straight line perpendicular to 5x – 2y = 8 and which passes through the mid-point of the line segment joining (2, 3) and (4, 5). Equation of the straight line. Given a straight line x cos 30° + y sin 30° = 2. "y=mx+b" is the formula of a straight line drawn on Cartesian coordinate system in which "y" is the vertical axis and "x" the horizontal axis. 1 decade ago. 1 answer. 3x −5y=15 3 x − 5 y = 15 Equation of a line Whenever we have an equation in the form ax+by =c a x + b y = c, the equation is that of a straight line which can be drawn in the cartesian plane. If you are unable to turn on Javascript, please click here. (C) a straight line with slope 1 and x intercept 3. 1 decade ago. Plug in . (C.B.S.E. Draw PQ parallel to y-axis cutting the line y = 3x at Q. Such an equation is usually written y=mx+b ("y=mx+c" in the UK). (B) a straight line with slope 2 and y intercept 2. We note that for x=0, the value of y is 3.000 and for x=2.000, the value of y is 1.800. The straight line 2x-y + 8 = 0 intersects the axes OX and OY at points A and B respectively. so in the given line: -3x + 5y - 15 = 0. sub in y = 0 to find the x-intercept: -3x - 15 = 0. x = -5. thus, the point (-5 , 0) will be on the desired line. Download this lesson as PDF:-Straight Lines PDF. Answer to: Use the intercepts to graph the equation 3x-5y=15. Explanation: Note that the given equation: #3x-5y=15# is a linear (straight line) equation with: #x#-intercept (value of #x# when #y=0#) of #x=5# and #y#-intercept (value of #y# when #x=0#) of #y=-3# Therefore we have the two points: #Gradient or Slope of a line The trigonometrical tangent of the angle that a line makes with the positive direction of the x-axis in anti-clockwise direction is called … Question 16. Regarding this formula, see the lesson The distance from a point to a straight line in a coordinate plane in this site. ∴ m = 3. Your straight line is 8x - 5y - 15 = 0. (a) Solution. Answer in Brief. Find the equation of the line passing through (0, 4) and parallel to the line 3x + 5y + 15 = 0. Add your answer and earn points. find the slope of a line parallel to 3x+5y=15? Answer: 1 question Find 5 solutions for the linear equation 3x-5y=15, and plot the solutions as points on a coordinate plane. Find the equation of the line passing through (0, 4) and parallel to the line 3x + 5y + 15 = 0. Rearrange the equation by subtracting what is to the right of the equal sign from both sides of the equation :                      3*x+5*y-(15)=0, 1.1     Solve   3x+5y-15  = 0 Tiger recognizes that we have here an equation of a straight line. So, the numbers in your case are a= 8, b= -5, c= -15, = -3, = 2. What is the general form of the line y = - x + 1? The co-ordinates of two points E and F are (0, 4) and (3, 7) respectively. Question 12. x – 2y = 5 3x – 6y = 15 Solution: x – 2y = 5 x = 5 + 2y Substituting some different values of y, we get corresponding values of x as shown below: Now plot these points on the graph and join them 3x – 6y = 15 => 3x = 15 + 6y x = \(\frac { 15 + … We know that distance (d) of a point (x1, y1) from a line Ax + By + C = 0 is d = |_1 + 〖〗_2 + |/√(^2 + ^2 ) Now, our equation is 3x – 4y – 26 = 0 The above equation is of the form The slope of the line is the value of , and the y-intercept is the value of . Answer: 1 question Find 5 solutions for the linear equation 3x-5y=15, and plot the solutions as points on a coordinate plane. Write down the equation of the line perpendicular to 3x +8y = 12 and passing through the point (-1, -2). QED. Lv 7. Must show work. C = 15. the desired line is : 3x + 4y + 15 = 0 Find the distance between the origin and the straight line 12x-5y+39=0. 1 0. esperism. So, every first degree equation in x and y represents a straight line. Find the point on the line 3x+y+4=0 which is equidistant from (-5,6) and (3,2) 2 See answers aditya200330 aditya200330 Hey bro your answer is -72.92. multiplying an odd number of negative factor equals a negative. Add your answer and earn points. The co-ordinates of the foot of perpendicular from A on the bisector of the angle between them are (A) 2 3, 2 (B) (0, 0) (C) 2 3,2 (D) (0, 4) Q.18 Point 'P' lies on the line l { (x, y) | 3x + 5y = 15}. Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Multiply … So we have two sample points #(0,15)# and #(5,0)# Since #3x+y=15# is a linear equation, we only need two points to establish the graph. Draw QN parallel to x-axis meeting y-axis at N. So, y = ON = -6. - the answers to estudyassistant.com 1 decade ago. View Answer The line x − 3 y + 7 = 0 intersects the pair of straight lines x 2 + 2 y 2 − 3 x y + 2 x − 5 y + 3 = 0 in two points A and B . P can lie in. Determine the equation of the other line which is parallel to it and passes through (4, 3). Question 16. 1. slope = -3/5. Solution: Question 21. 8 Answers. This site is best viewed with Javascript. We shall now graph the line  3x+5y-15  = 0 and calculate its properties, Notice that when x = 0 the value of y is 3/1 so this line "cuts" the y axis at y= 3.00000, When y = 0 the value of x is 5/1 Our line therefore "cuts" the x axis at x= 5.00000, Slope is defined as the change in y divided by the change in x. a. rewrite each line in slope-intercept form. C is the See answer jf9375254 is waiting for your help. What is the solution to the system of equations 5x + 5y = 15 and 2x + 2y = 6? Consider the lines given by 2x-3y = 12 and 3x + 5y =15. ∴ m = 3. Slope of a line which cuts off intercepts of equal lengths on the axes is (a) – 1 (b) – 0 (c) 2 (d) √3 Ans. the x-intercept is the point where y = 0. so in the given line: -3x + 5y - 15 = 0. sub in y = 0 to find the x-intercept:-3x - 15 = 0. x = -5. thus, the point (-5 , 0) will be on the desired line. 5y = - 3x + 15. y = (-3/5) x + 3. m = - 3/5 is slope of line . 1. Find the distances of the points A (4, 3), B (2, 1), and C(1, 0) from the straight line 3x+4y-I0=0. A point which is equidistant from both the axes lies on either y = x and y = -x. A point on the straight line, 3x + 5y =15 which is equidistant from the coordinate axes will lie only in: (2019) (1) 4 th quadrant (2) 1 st quadrant (3) 1 st and 2 nd quadrants (4) 1 st, 2 nd and 4 th quadrants Ans. b= y-intercept. The value of 't' is What best explains the fact that there are very few averages in the lowest class? (D) a circle Q.5 m, n are integer with 0 < n < m. A is the point (m, n) on the cartesian plane. Parallel line will have same slope. Slope-intercept form y mx b ; Use the y-intercept and the slope. 10 Assignment. Let the straight line in a coordinate plane is defined in terms of its linear equation a*x + b*y + c = 0, where "a", "b" and "c" are real numbers, and let P = ,) be the point in the coordinate plane. The equation is, ax + by + c = 0; so, in intercept form it … 9 Graphing equations in different forms. See answer jf9375254 is waiting for your help. The line segment joining the points A(3, -4) and B (-2, 1) is divided in the ratio 1: 3 at point P in it. 2004) Solution: 4x – 5y – 20 = 0 => 4x = 5y + 20 x = \(\frac { 5y + 20 }{ 2 }\) Substituting some different values of y, we get their corresponding values of x as shown below Then the distance from the point P … 3x-5y=-15 Answer by jim_thompson5910(35256) (Show Source): You can put this solution on YOUR website! Find Any Equation Parallel to the Line y=-3x+5. Q.16. Point-slope form y y1 m(x x1) Use a point (x1, y1 ) and the slope, m. Standard form Ax By C ; Rewrite in y mx b form OR ; Find the x-intercept and the y-intercept OR ; Make a table of solutions. Find the equation of the line. 15=3x. 1 … Find the co-ordinates of P. Also, find the equation of the line through P and perpendicular to the line 5x – 3y + 4 = 0. Now find the intersection of the two lines: Such an equation is usually written y=mx+b ("y=mx+c" in the UK). Straight line given by points A[0; 3] and B[5; 0] Calculation: Slope-intercept form of line: y = -0.6x+3 Canonical form of the line equation: 3x+5y-15 = 0 Parametric form of the line equation: x = 5t y = -3t+3 ; t ∈ R Slope: m = -0.6 Slope angle of line: φ = -30°57'50″ = -0.5404 rad X intercept: x 0 = 5 Y intercept: y 0 = q = 3 Distance line from the origin: d 0 = 2.5725 The length of the segment AB: |AB| = 5.831 Vector: AB … 3x+5y=15 Geometric figure: Straight Line Slope = -1.200/2.000 = -0.600 x-intercept = 15/3 = 5 y-intercept = 15/5 = 3 Rearrange: Rearrange the equation by subtracting what is to the ... 3x+5y=16 3 x + 5 y = 1 6 So the x-intercept is . how steep the line isb is the Y-intercept i.e. Take a point P on the left of y-axis such that the distance of point P from the y-axis is 2 units. A line through B, perpendicular to l 1 cuts the y-axis at P(0,t). Favorite Answer. Choose to substitute in for to find the ordered pair. Question 17. Solution Show Solution. Equation of the straight line. Answer to: Use the intercepts to graph the equation 3x-5y=15. A point M divides AB in the ratio AM:MB=3:1. Which graph represents -3x+5y=-15? Such an equation is usually written y=mx+b ("y=mx+c" in the UK). Given that: tan θ = 3/5 ⇒ Slope of the line m = 3/5 So, the equation of the line is y – y 1 = m(x – x 1) ⇒ ⇒ 5y + 15 = 3x ⇒ 3x – 5y – 15 = 0 ⇒ 5y - 3x + 15 = 0 Hence, the correct option is (a). Use the slope and a given point to substitute for and in the point-slope form, which is derived from the slope equation. Solution Show Solution The equation of the line in intercept form is \[\frac{x}{a} + \frac{y}{b} = 1\]. 3x + 5y = 18. [2] CAREER POINT CAREER POINT Ltd., CP Tower, IPIA, Road No.1, Kota (Raj. "y=mx+b" is the formula of a straight line drawn on Cartesian coordinate system in which "y" is the vertical axis and "x" the horizontal axis. - Mathematics. Find the equation of a straight line passing through the intersection of 2x + 5y – 4 = 0 with x-axis and parallel to the line 3x – 7y + 8 = 0. Solution: Question 10. The co-ordinates of the foot of perpendicular from A on the bisector of the angle between them are (A) 2 3, 2 (B) (0, 0) (C) 2 3, 2 (D) (0, 4) Q.18 Point 'P' lies on the line l { (x, y) | 3x + 5y = 15}. P can lie in - Sarthaks eConnect | Largest Online Education Community A point P on the line 3x + 5y – 15 = 0 is equidistant from the coordinates axes. we can use this to solve for C. 3(-5) + C = 0-15 + C = 0. ANS: (0.5, 0.5) PTS: 1 REF: The Basics of the Plane 3. Let PQ be the straight line having AB, the line segment between the axes. From above graph, we can see that, Point A (1, 4) is already plotted on the graph, and a point of intersection of two intersecting lines. Reduce. Slope: ... Any line can be graphed using two points. Find the distance between the origin and the straight line 12x-5y+39=0. Thus, equation to straight line is 3x – 4y + 5 = 0 (iii) Equation of line parallel to line 2x + 5y = 7 2x + 5y = c …(i) Mid point of line joining the points (2,7) and (-4, 1) Putting this value in equation (i), ⇒ 2 × (-1) + 5 × (4) = c ⇒ -2 + 20 = c ⇒ c = 18 Thus, Required equation of line is 2x + 5y = 18 (iv) Equation of line passing through the points (- 3, 7) and (5, – 4) Equation of line perpendicular to this line 11y – 8x … Draw a straight line through the intercept points as indicated below. Find the equation of the straight line which has Y-intercept equal to 4/3 and is perpendicular to 3x – 4y + 11 = 0. asked Feb 28, 2019 in Class X Maths by aditya23 (-2,145 points) coordinate geometry. 1.1 Solve 3x+5y-15 = 0 Tiger recognizes that we have here an equation of a straight line. Draw a straight line through the intercept points as indicated below. Some important points to remember #Straight Line A straight line is a curve , such that every point on the line segment joining any two points on it lies on it. your y-intercept is (0,-3) because the "b" (y=mx+b) is -3. If you need to find a line given two points or a slope and one point, use line … Where, => m = gradient, If two lines are perpendicular , m1.m2=-1 -----Acc to question, Given line is y=3x+1. Do the following to find the point where the two lines INTERSECT(where they cross). Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students. i have no idea how to do this. 3x+5y=15 Geometric figure: Straight Line Slope = -1.200/2.000 = -0.600 x-intercept = 15/3 = 5 y-intercept = 15/5 = 3 Rearrange: Rearrange the equation by subtracting what is to the ... 3x+5y=16 3 x + 5 y = 1 6 Given that two lines are perpendicular, (3) Solution. of required line is:- y-1= 4/3.(x-5). In the special case where the two mirror points become one on the symmetry line, so do their chord lines, which become parallel to the given line MarcPearce MarcPearce Answer: It's a straight line Step-by-step explanation: The line has a slope of 3/5 and a y-axis crossing of -3 New questions in Mathematics. Casey.T. Find the equation of the line passing through (0, 4) and parallel to the line 3x + 5y + 15 = 0. asked Feb 27, 2019 in Class X Maths by priya12 (-12,630 points) coordinate geometry. 104. Anonymous. Let the equation of a line is 3x + 5y = 15 and a point P on this line is equidistant from x and y axis. bibek2619 bibek2619 Let the point on the line 3x+y+4=0 equidistant from points A (-5,6)and B (3,2) be … m=slope. x-intercept To find the x-intercept, plug in and solve for x Start with the given equation. Answer Save. ... Now draw a straight line through the plotted points to graph . Multiply and 0 to get 0. ~~~~~ There is a remarkable formula to calculate the distance from a given point to a given straight line in a coordinate plane. - the answers to estudyassistant.com Find the equation of the straight line which has Y-intercept equal to 4/3 and is perpendicular to 3x – 4y + 11 = 0. MarcPearce MarcPearce Answer: It's a straight line Step-by-step explanation: The line has a slope of 3/5 and a y-axis crossing of -3 New questions in Mathematics. Find the equation of the straight line passing through the point (2, 1) and bisecting the portion of the straight line 3x − 5y = 15 lying between the axes. Plot the points and the straight line. Find the Distance of the Point (4, 5) from the Straight Line 3x − 5y + 7 = 0. where the line crosses the Y axisThe X and Y intercepts and the Slope are called the line properties. ----- y-intercept To find the y-intercept, plug in and solve for y Start with the given equation. Which graph represents -3x+5y=-15? to the line passing through the point (, ) Enter the equation of a line in any form: y=2x+5 , x-3y+7=0 , etc. Q.23. point slope form: y=mx +b. Q.12 A point on the straight line, 3x + 5y = 15 which is equidistant from the coordinate axes will lie only in - (1) 1st, 2nd and 4th quadrants (2) 1st and 2nd quadrants (3) 4th quadrants (4) 1st quadrants Ans. x=5. Find the equation of the line passing through (0, 4) and parallel to the line 3x + 5y + 15 = 0. asked Feb 27, 2019 in Class X Maths by priya12 ( -12,630 points) coordinate geometry 5y + 15 = -3x + 33. In which quadrant the point P lies? -5,6and multiply 3.2 = (-5,6) and multiply 3.2 and then calculate it to get answer. e.g. Q.17 A is a point on either of two lines y + 3 x = 2 at a distance of 4 3 units from their point of intersection. Plot points (1,3) and (2,6) on a graph paper and join them to get the required graph. So, a line that extends to both sides till infinity and has no curves is called a straight line. Find the equation of the line that is perpendicular to 3x + 2y – 8 = 0 and passes through the mid-point of the line segment joining the points (5, -2), (2, 2). Must show work. Given that two lines are perpendicular, harry m. Lv 6. Slope of a line perpendicular to 3x+4y-5=0 will be = 4/3. 5y=3x … Hint. A straight line passes through the point (3, 2) and the portion of this line, intercepted between the positive axes, is bisected at this point. ... Find the parallel line using the point-slope formula. Find the equation of the straight line which has Y-intercept equal to 4/3 and is perpendicular to 3x – 4y + 11 = 0. Como. C = 15. the desired line is : 3x + 4y + 15 = 0. and by the way, all lines parallel to -3x + 5y - 15 = 0 will look like: -3x + 5y + C = 0 (coefficients of x and y will stay the same, just the constant will change) 0 0. Question 15. eq. Q.17 A is a point on either of two lines y + 3 x = 2 at a distance of 4 3 units from their point of intersection. A point P on the line 3x + 5y – 15 = 0 is equidistant from the coordinates axes. 4x-20 = 3y-3. use point- slope form to get the equation of the line: y - 5 = -5/3(x - 2) y = -5/3 x + 10/3 + 5. y = -5/3 x + 25/3. Plug in . Note that the configuration is symmetric with respect to the line passing through origin and perpendicular to $3x-4y+12=0$. Find the equation of the line. Show that the straight lines 2x-3y=6 and 4x-6y= = 25 … A straight line is passing through the point (1, 2) and parallel to the line y = 3x + 1 . The relation between variables x, y satisfy all points on the curve. If a straight line passing through the point P(–3, 4) is such that its intercepted portion between the coordinate axes, A straight line L at a distance of 4 units from the origin makes positive intercepts on the coordinate axes and the perpendicular from the origin to. Simplify. Find the equation of the straight line perpendicular to 5x – 2y = 8 and which passes through the mid-point of the line segment joining (2, 3) and (4, 5). And to get the the x-intercept, you set y equalt o zero and you get: 0=3/5x-3. y= 3/5x-3. Slope = 3/5, so perpendicular slope = -5/3. 2. Answer 14. x+y=0, 3x-y+2=0, y+1=0, y=0. x-intercept= (5,0) =) 1 0. The straight line x + 2y = 1 meets the coordinate axes at A and B. A straight line l 1 with equation x-2y+10=0 meets the circle with equation x 2 + y 2 = 1 0 0 at B in the first quadrant. First isolate y to get standard form:-5y=-3x+15. Equation of Straight Line. a. rewrite each line in slope-intercept form. Do the following to find the point where the two lines INTERSECT(where they cross). Given a straight line with equation coefficients as a, b & c(ax + by + c = 0), the task is to find the area of the triangle formed by the axes of co-ordinates and this straight line.. Find the distances of the points A (4, 3), B (2, 1), and C(1, 0) from the straight line 3x+4y-I0=0. 106. 3x + 5y – 15 = 0 Determine the vertices of the triangle formed by the lines representing the above equation and the y-axis. Straight line given by points A[0; 3] and B[5; 0] Calculation: Slope-intercept form of line: y = -0.6x+3 Canonical form of the line equation: 3x+5y-15 = 0 Parametric form of the line equation: Find the equation of the line which is parallel to 3x -2y -4 = 0 and passes through the point (0, 3). 3x+5y=15 => 5y= -3x+15 => y= -3/5 x+15/5 => y= m x+c. ANS: x + y - 1 = 0 PTS: 1 REF: The Equation of a Straight Line 4. asked Feb 28, 2019 in Class X Maths by aditya23 ( -2,145 points) A point P on the line 3x + 5y – 15 = 0 is equidistant from the coordinates axes. Yes, the line 3x = y + 1 is the bisector. x and y intercept of straight line 3x-5y=15? Example 18 Find the distance of the point (3, –5) from the line 3x – 4y –26 = 0. A point on the straight line, 3x + 5y = 15 which is equidistant from the coordinate axes will lie only in -, Correct option  (2)  1st and 2nd quadrants. ), Ph: 0744-6630500 www.careerpoint.ac.in 6 JEE Main Online Paper Sol. 3x + 5y = 15 equation of straight line x = y 8x = 15 … asked Feb 28, 2019 in Class X Maths by aditya23 ( -2,145 points) "y=mx+b" is the formula of a straight line drawn on Cartesian coordinate system in which "y" is the vertical axis and "x" the horizontal axis.In this formula :y tells us how far up the line goesx tells us how far alongm is the Slope or Gradient i.e. So, for a change of 2.000 in x (The change in x is sometimes referred to as "RUN") we get a change of 1.800 - 3.000 = -1.200 in y. … Plotting these points and drawing a line through them gives us a graph that should look like: A point on the straight line, 3x + 5y = 15 which is equidistant from the coordinate axes will lie only in - (1) 1st, 2nd and 4th quadrants (2) 1st and 2nd quadrants (3) 4 th quadrants B is the reflection of A in the line y = x. For any pair of mirror points on the given line, the midpoints of their tangent chord line are also mirror points. Relevance. 0 votes. Find the equation of a line passing through (3, – 2) and perpendicular to the line. This deals with the properties of a straight line. Question 14. Comparing ax + by + c = 0 and 3x − 5y + 7 = 0, we get: P can lie in What is the midpoint of the line segment between the two points (-3, 2) and (4, 0)? Where, => m = gradient, If two lines are perpendicular , m1.m2=-1 -----Acc to question, Given line is y=3x+1. Hence, it is proved that the straight line passing through (3, 5) and (-1, 3) and also passes through A (1, 4). Find the equation of a line passing through (3, – 2) and perpendicular to the line. Explanation: Note that the given equation: #3x-5y=15# is a linear (straight line) equation with: #x#-intercept (value of #x# when #y=0#) of #x=5# and #y#-intercept (value of #y# when #x=0#) of #y=-3# Therefore we have the two points: Find (i) the gradient of EF (ii) … Find the distance of the point (4, 5) from the straight line 3x − 5y + 7 = 0. (A) a straight line with slope 1 and y intercept 3. A circle is drawn through A, B and the origin. x-intercept To find the x-intercept, plug in and solve for x Start with the given equation. Equation of the given line is x cos 30° + y sin 30° = 2 y sin 36° = -x cos 30° + 2. Show that the straight lines 2x-3y=6 and 4x-6y = = 25 are parallel, and find the distance between them. Find the distance of the line 8x-5y-15=0 from the point (-3,2). 4x-3y = 17 .Answer. Intercept form of a line is ⇒ (∴ a = b) ⇒ x + y = a ⇒ y = – x + a ∴ Slope is – 1 Hence, the correct option … A straight line is passing through the point (1, 2) and parallel to the line y = 3x + 1 . Writr the equation of the perpendicular erected to AB at the point M. 98. 105. Question 15 3x-5y=-15 Answer by jim_thompson5910(35256) (Show Source): You can put this solution on YOUR website! First, get the original line in y = mx + b form: 5y = 3x - 3. y = 3/5 x - 3/5. (The change in y is sometimes referred to as "RISE" and the Slope is m = RISE / RUN), Beginning Algebra Tutorial 11: Simplifying Algebraic Expressions. Knowledge required: General equation of a line is y=mx+c. Divide both sides by to isolate . Slope of 3x+4y-5 = 0 is = -3/4. Then graph the line. Question By default show hide Solutions. 1.1 Solve 3x-5y+15 = 0 Tiger recognizes that we have here an equation of a straight line. Closest point will be on the perpendicular from (2,5) to the line. Simplify the equation and keep it in point-slope form. 0 votes. … 1 … 1 0. 104. slope of a line parallel = -3/5. Solution: Given points, A (3, -4) and B (-2, 1) By section formula, the co-ordinates of the point P which divides AB in the ratio 1: 3 is given by = (7/4, -11/4) = (x 1, y 1) … 6.4 19-45 odds ; Due Wednesday 1/14/04 ; 6.5 13-25 … Select two values, and plug them into the equation to find the corresponding values. The number of integer values of λ for which the x-coordinates of the point of intersection of the lines 3x + 4y = 9 and y = λ x + 1 is also an integer is m . Find the equation of a straight line parallel to the line 2x +3y = 5 and having the same y-intercept as x +y +4 = 0. 105. Now plot the points of both lines on the graph and join them, we see that all the points lie on the same straight line This system has infinitely many solutions. Plug in . Question 17. 1 decade ago. 3=3/5x. Knowledge required: General equation of a line is y=mx+c. Plot the points and the straight line. Examples: Input: a = -2, b = 4, c = 3 Output: 0.5625 Input: a = 4, b = 3, c = 12 Output: 6 Approach:. The general equation of straight line is as given below: ax + by + c = 0 { equation of straight line. Graph the linear function d(x)=−1/2x−3 I need to know … Take an arbitrary point on one of the lines and find its distance from the other line. 2 Answers. Answer Save. Consider the lines given by 2x-3y = 12 and 3x + 5y =15. Question 15. we can use this to solve for C. 3(-5) + C = 0-15 + C = 0. 97. Then the distance from the point P to the straight line is equal to d = . Solution: What is the terminal point of a line segment extending three times its own … Determine the coordinates of the point which is three-fifths of the way If (-2, -4) is the midpoint of (6, -7) and (x, y), what are x … parallel means to have the same slope but different y-intercept. Point slope form of above is y= -3x/5 + 15 y-intercept of the line 3x 5y 15. Favorite Answer . , the numbers in your case are a= 8, b= -5, c= -15 =! Has y-intercept equal to d = erected to AB at the point ( -1, -2.... Axes at a and B respectively because the `` B '' ( ). = -5/3 1, 2 ) and ( 2,6 ) on a graph paper and join them get! Slope 2 and y represents a straight line is equal to 4/3 and perpendicular. ) is -3 5y= -3x+15 = > 5y= -3x+15 = > 5y= -3x+15 >. Into the equation of a line is passing through ( 3, – 2 and! Their tangent chord line are also mirror points on the line represents a straight line see lesson... Form: -5y=-3x+15 a given straight line 3x − 5y + 7 = 0.! Distance between the origin `` B '' ( y=mx+b ) is -3 line y =.. To it and passes through ( 4, 5 ) from the y-axis is units! = > y= -3/5 x+15/5 = > y= -3/5 x+15/5 = > -3/5! There are very few averages in the UK ) that for x=0, the of! Be the straight line draw QN parallel to x-axis meeting y-axis at P 0... Line 12x-5y+39=0. ( x-5 ) cross ) -3, = -3, = 2 and intercept... 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B= -5, c= -15, = -3, = 2 = 3x at Q Sarthaks eConnect: a platform. To turn on Javascript, please click here is passing through ( 3, – 2 ) and parallel y-axis! The value of y is 1.800 draw QN parallel to y-axis cutting the line perpendicular to l cuts. 3X − 5y + 7 = 0 is = -3/4 - y-1= 4/3. ( x-5 ) lie parallel... At the point where a point on the straight line 3x+5y=15 two lines INTERSECT ( where they cross ) means to have same... For and in the line crosses the y axisThe x and y intercepts the! C = 0 is equidistant from the point P from the y-axis is 2 units axes OX and OY points... The fact that there are very few averages in the lowest class and the slope and a given straight is! Tiger recognizes that we have here an equation is usually written y=mx+b ( `` ''... Jim_Thompson5910 ( 35256 ) ( Show Source ): you can put this solution on your!! You get: 0=3/5x-3 36° = -x cos 30° + 2 + 4y + 11 = 0 the... So, y satisfy all points on the line y = 3x at Q and join them to get.... ~~~~~ there is a remarkable formula to calculate the distance between them... find point! What best explains the fact that there are very few averages in the class. + 2y = 1 meets the coordinate axes at a and B -.. ( x-5 ) ) from the y-axis at N. so, y satisfy all on... Axisthe x and y represents a straight line in a coordinate plane and F are (,... 0-15 + C = 0 y to get the required graph: Use slope! Is slope of a line passing through the point M. 98 -3x+15 = > 5y= -3x+15 = y=!